Question Number 120519 by bemath last updated on 01/Nov/20
Commented by bemath last updated on 01/Nov/20
$$\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x}\:. \\ $$$$\left(\mathrm{a}\right)\mathrm{2}\:\:\:\:\left(\mathrm{b}\right)\mathrm{3}\:\:\:\:\:\left(\mathrm{c}\right)\mathrm{4}\:\:\:\:\left(\mathrm{d}\right)\mathrm{5}\:\:\:\:\left(\mathrm{e}\right)\mathrm{8} \\ $$
Answered by $@y@m last updated on 01/Nov/20
$$\left({A}\right)\:\left(\mathrm{7}−\mathrm{4}\right)^{\mathrm{2}} +\left(\mathrm{5}−\mathrm{3}\right)^{\mathrm{2}} =\mathrm{13} \\ $$$$\left({B}\right)\:\left(\mathrm{4}−\mathrm{1}\right)^{\mathrm{2}} +\left(\mathrm{9}−\mathrm{8}\right)^{\mathrm{2}} =\mathrm{10} \\ $$$$\left({C}\right)\:\left(\mathrm{5}−\mathrm{4}\right)^{\mathrm{2}} +\left(\mathrm{7}−\mathrm{6}\right)^{\mathrm{2}} =\mathrm{2} \\ $$$${Ans}.\left({a}\right)\:\mathrm{2} \\ $$
Commented by bemath last updated on 01/Nov/20
$$\mathrm{coll}…\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$