Question Number 120676 by I want to learn more last updated on 01/Nov/20
Commented by som(math1967) last updated on 02/Nov/20
$$\mathrm{BC}+\mathrm{AC}−\mathrm{AB} \\ $$$$=\mathrm{5}+\mathrm{6}−\mathrm{3}=\mathrm{8unit} \\ $$
Commented by som(math1967) last updated on 02/Nov/20
Commented by som(math1967) last updated on 02/Nov/20
$$\mathrm{CD}+\mathrm{DE}+\mathrm{EC} \\ $$$$=\mathrm{CD}+\mathrm{DM}+\mathrm{ME}+\mathrm{EC} \\ $$$$=\mathrm{CD}+\mathrm{DN}+\mathrm{OE}+\mathrm{EC}\:\bigstar \\ $$$$=\mathrm{CN}+\mathrm{CO} \\ $$$$=\mathrm{AC}−\mathrm{AN}+\mathrm{BC}−\mathrm{BO} \\ $$$$=\mathrm{AC}+\mathrm{BC}−\left(\mathrm{AL}+\mathrm{BL}\right)\bigstar\bigstar \\ $$$$=\mathrm{AC}+\mathrm{BC}−\mathrm{AB} \\ $$$$=\mathrm{6}+\mathrm{5}−\mathrm{3}=\mathrm{8unit} \\ $$$$\bigstar\mathrm{DM}=\mathrm{DN},\mathrm{ME}=\mathrm{OE} \\ $$$$\bigstar\bigstar\mathrm{AN}=\mathrm{AL},\mathrm{BO}=\mathrm{BL} \\ $$$$ \\ $$
Commented by I want to learn more last updated on 02/Nov/20
$$\mathrm{Thanks}\:\mathrm{sir} \\ $$