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Question-121100




Question Number 121100 by Ar Brandon last updated on 05/Nov/20
Answered by TANMAY PANACEA last updated on 05/Nov/20
((logx)/(x(y+z−x)))=((logy)/(y(z+x−y)))=((logz)/(z(x+y−z)))=k  logx=kx(y+z−x)  logy=ky(z+x−y)  logz=kz(x+y−z)  A)x^y y^x =p  ylogx+xlogy=logp  ykx(y+z−x)+kxy(z+x−y)=logp  xyk(y+z−x+z+x−y)  xyk(2z)=2xyz×k  y^z z^y =Q  zlogy+ylogz=logQ  zky(z+x−y)+ykz(x+y−z)=logQ  yzk(2x)  2xyzk  so logp=logQ  so option A is correct...  pls check same way option (B,C,D) pls
logxx(y+zx)=logyy(z+xy)=logzz(x+yz)=klogx=kx(y+zx)logy=ky(z+xy)logz=kz(x+yz)A)xyyx=pylogx+xlogy=logpykx(y+zx)+kxy(z+xy)=logpxyk(y+zx+z+xy)xyk(2z)=2xyz×kyzzy=Qzlogy+ylogz=logQzky(z+xy)+ykz(x+yz)=logQyzk(2x)2xyzksologp=logQsooptionAiscorrectplschecksamewayoption(B,C,D)pls
Commented by Ar Brandon last updated on 05/Nov/20
Thank you Sir. It is a multiple correct choice type question.
Commented by TANMAY PANACEA last updated on 05/Nov/20
most welcome sir
mostwelcomesir

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