Question Number 121380 by aurpeyz last updated on 07/Nov/20
Answered by TANMAY PANACEA last updated on 07/Nov/20
$$\underset{{x}\rightarrow\mathrm{0}.\mathrm{5}−\:\frac{}{}} {\mathrm{li}{m}} \\ $$$${li}\underset{{x}\rightarrow\mathrm{0}.\mathrm{5}−} {{m}}\:\sqrt{\frac{{x}+\mathrm{2}}{{x}+\mathrm{1}}}\:=\sqrt{\frac{\mathrm{2}.\mathrm{5}}{\mathrm{1}.\mathrm{5}}}\:=\sqrt{\frac{\mathrm{5}}{\mathrm{3}}}\: \\ $$$$\boldsymbol{{i}}\:\boldsymbol{{think}}\:\boldsymbol{{so}} \\ $$$$ \\ $$$$ \\ $$
Answered by TANMAY PANACEA last updated on 07/Nov/20
$$\left.\mathrm{2}\right){li}\underset{{h}\rightarrow\mathrm{0}} {{m}}\:\:{f}\left({h}\right)\rightarrow\infty \\ $$