Question Number 121442 by bramlexs22 last updated on 08/Nov/20
Answered by liberty last updated on 08/Nov/20
Answered by Don08q last updated on 09/Nov/20
$$\:{y}^{\mathrm{2}} −\mathrm{3}{xy}+{x}^{\mathrm{2}} −{x}+{y}+\mathrm{9}=\mathrm{0} \\ $$$$\:{y}^{\mathrm{2}} −\mathrm{2}{xy}+{x}^{\mathrm{2}} −{xy}+{y}−{x}+\mathrm{9}=\mathrm{0} \\ $$$$\:\left({y}−{x}\right)^{\mathrm{2}} +\left({y}−{x}\right)+\mathrm{9}={xy} \\ $$$$\:\left(\mathrm{2}\right)^{\mathrm{2}} +\left(\mathrm{2}\right)+\mathrm{9}={xy} \\ $$$$\:{xy}\:=\:\mathrm{15} \\ $$$$\: \\ $$