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Question-121807




Question Number 121807 by abdelsalamalmukasabe last updated on 11/Nov/20
Answered by sukumara3@gmail.com last updated on 14/Nov/20
while cancelling step,it is not 2yy^′ x.But it is 2y^′ y^′ x only.
$${while}\:{cancelling}\:{step},{it}\:{is}\:{not}\:\mathrm{2}{yy}^{'} {x}.{But}\:{it}\:{is}\:\mathrm{2}{y}^{'} {y}^{'} {x}\:{only}. \\ $$

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