Question-122010

Question Number 122010 by I want to learn more last updated on 13/Nov/20

Answered by TANMAY PANACEA last updated on 13/Nov/20

2 x - 5 = \frac{8}{x} + 10

2 x^{2} - 5 x = 8 + 10 x

2 x^{2} - 15 x - 8 = 0

2 x^{2} - 16 x + x - 8 = 0

2 x (x - 8) + 1 (x - 8) = 0

(x - 8) (2 x + 1) = 0

x = 8, \frac{- 1}{2}

g (8) = 2 \times 8 - 5 = 11 h (8) = \frac{8}{8} + 10 = 11

f (8) = 2^{8 - 5} + 3 = 11

f (8) = g (8) = h (8)

g (\frac{- 1}{2}) = 2 \times \frac{- 1}{2} - 5 = - 6

h (\frac{- 1}{2}) = \frac{8}{- 1} \times 2 + 10 = - 6

f (\frac{- 1}{2}) = 2^{\frac{- 1}{2} - 5} + 3

f (\frac{- 1}{2}) \neq g (\frac{- 1}{2})

f (\frac{- 1}{2}) \neq h (\frac{- 1}{2})

s o x = 8 f (8) = g (8) = h (8)

Commented by I want to learn more last updated on 13/Nov/20

Thanks sir .

Commented by TANMAY PANACEA last updated on 14/Nov/20

m o s t w e l c o m e