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Question-122540




Question Number 122540 by help last updated on 18/Nov/20
Commented by help last updated on 18/Nov/20
find the perimeter of the shape
$${find}\:{the}\:{perimeter}\:{of}\:{the}\:{shape} \\ $$
Answered by Olaf last updated on 18/Nov/20
above : 4.7+3+(π/2)(11.2−4.7−3)  right : 3.5+3.5+(π/2)(14−3.5−3.5)  below : (π/2)×11.2  left : 14    total : (7.7+1.75π)+(7+3.5π)+(5.6π)+14  = 28.7+10.85π
$$\mathrm{above}\::\:\mathrm{4}.\mathrm{7}+\mathrm{3}+\frac{\pi}{\mathrm{2}}\left(\mathrm{11}.\mathrm{2}−\mathrm{4}.\mathrm{7}−\mathrm{3}\right) \\ $$$$\mathrm{right}\::\:\mathrm{3}.\mathrm{5}+\mathrm{3}.\mathrm{5}+\frac{\pi}{\mathrm{2}}\left(\mathrm{14}−\mathrm{3}.\mathrm{5}−\mathrm{3}.\mathrm{5}\right) \\ $$$$\mathrm{below}\::\:\frac{\pi}{\mathrm{2}}×\mathrm{11}.\mathrm{2} \\ $$$$\mathrm{left}\::\:\mathrm{14} \\ $$$$ \\ $$$$\mathrm{total}\::\:\left(\mathrm{7}.\mathrm{7}+\mathrm{1}.\mathrm{75}\pi\right)+\left(\mathrm{7}+\mathrm{3}.\mathrm{5}\pi\right)+\left(\mathrm{5}.\mathrm{6}\pi\right)+\mathrm{14} \\ $$$$=\:\mathrm{28}.\mathrm{7}+\mathrm{10}.\mathrm{85}\pi \\ $$

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