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Question-122705




Question Number 122705 by john santu last updated on 19/Nov/20
Commented by liberty last updated on 19/Nov/20
⇒a : b = 2 : 3   ⇒b : c = 3 : 4  ⇒ c : d = 5 : 6   then a : b : c : d = 10 : 15 : 20 : 24  we get a+b+c+d = 69k = 21.2  k = ((21.2)/(69)) = ((106)/(345))   { ((a=10k , b = 15k)),((c=20k , d=24k)) :}
$$\Rightarrow{a}\::\:{b}\:=\:\mathrm{2}\::\:\mathrm{3}\: \\ $$$$\Rightarrow{b}\::\:{c}\:=\:\mathrm{3}\::\:\mathrm{4} \\ $$$$\Rightarrow\:{c}\::\:{d}\:=\:\mathrm{5}\::\:\mathrm{6}\: \\ $$$${then}\:{a}\::\:{b}\::\:{c}\::\:{d}\:=\:\mathrm{10}\::\:\mathrm{15}\::\:\mathrm{20}\::\:\mathrm{24} \\ $$$${we}\:{get}\:{a}+{b}+{c}+{d}\:=\:\mathrm{69}{k}\:=\:\mathrm{21}.\mathrm{2} \\ $$$${k}\:=\:\frac{\mathrm{21}.\mathrm{2}}{\mathrm{69}}\:=\:\frac{\mathrm{106}}{\mathrm{345}} \\ $$$$\begin{cases}{{a}=\mathrm{10}{k}\:,\:{b}\:=\:\mathrm{15}{k}}\\{{c}=\mathrm{20}{k}\:,\:{d}=\mathrm{24}{k}}\end{cases} \\ $$

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