Question Number 122945 by CanovasCamiseros last updated on 21/Nov/20
Commented by CanovasCamiseros last updated on 21/Nov/20
$$\boldsymbol{{Question}}\:\left(\boldsymbol{{b}}\right) \\ $$
Answered by TANMAY PANACEA last updated on 21/Nov/20
$$\left.{a}\right)\frac{{ds}}{{dt}}={u}+\frac{\mathrm{1}}{\mathrm{2}}{a}×\mathrm{2}{t}={u}+{at} \\ $$$$\left.{b}\right)\frac{{dp}}{{d}\theta}=\mathrm{1}−\frac{\mathrm{3}\theta^{\mathrm{2}} }{\mathrm{6}}+\frac{\mathrm{5}\theta^{\mathrm{4}} }{\mathrm{120}}=\mathrm{1}−\frac{\theta^{\mathrm{2}} }{\mathrm{2}}+\frac{\theta^{\mathrm{4}} }{\mathrm{24}} \\ $$$$\left.{c}\right)\frac{{dA}}{{dR}}=\mathrm{2}\pi×\mathrm{2}{R}=\mathrm{4}\pi{R} \\ $$
Commented by CanovasCamiseros last updated on 21/Nov/20
$$\boldsymbol{{Thank}}\:\boldsymbol{{you}}\:\boldsymbol{{so}}\:\boldsymbol{{much}}! \\ $$