Question-122954

Question Number 122954 by mr W last updated on 21/Nov/20

Commented by Dwaipayan Shikari last updated on 21/Nov/20

I n f i n i t e l y m a n y a n s w e r s s i r!

I f t h e y a r e i n a r e l a t i o n C = 1 + (n - 1)

t h e n 12 w i l l c o s t 12 $ (f o r t h e p e o p l e w h o \dots . .)

I f t h e y a r e i n a r e l a t i o n

n + (n - 1) (n - 2) (n - 3) \dots (n - 11)

I f n = 12

t h e n p r i c e w i l l b e 12 + 11! $ :)

\dots \dots

Commented by prakash jain last updated on 22/Nov/20

Information about 2 and 11 is

redundant .

12 = 12 times ONE

So 12 will cost $ 12 .

Commented by mr W last updated on 22/Nov/20

a n o t h e r p o s s i b i l i t y :

s a y a l e t t e r O c o s t s o $, a l e t t e r N

c o s t s n $, e t c .

o + n + e = 1 \dots (i)

t + w + o = 2 \dots (i i)

3 e + l + v + n = 11 \dots (i i i)

(i i i) + (i i) - (i) :

2 e + l + v + t + w = 12 \dots (i v)

T W E L V E c o s t s 2 e + t + w + l + v, t h a t

i s 12 $ f r o m (i v) .

Facebook Tweet Pin