Question Number 123616 by aurpeyz last updated on 26/Nov/20
Answered by TANMAY PANACEA last updated on 26/Nov/20
$${d}\overset{\rightarrow} {{F}}={id}\overset{\rightarrow} {{l}}×\overset{\rightarrow} {{B}} \\ $$$${dF}={idlBsin}\theta\:\:\:{i}={current} \\ $$$${dl}={length}\:{of}\:{wire} \\ $$$${B}={magnetic}\:{field}\:{strength} \\ $$$$\theta={angle}\:{between}\:{B}\:{and}\:{i} \\ $$
Commented by aurpeyz last updated on 26/Nov/20
$${thanks} \\ $$