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Question-123616




Question Number 123616 by aurpeyz last updated on 26/Nov/20
Answered by TANMAY PANACEA last updated on 26/Nov/20
dF^→ =idl^→ ×B^→   dF=idlBsinθ   i=current  dl=length of wire  B=magnetic field strength  θ=angle between B and i
$${d}\overset{\rightarrow} {{F}}={id}\overset{\rightarrow} {{l}}×\overset{\rightarrow} {{B}} \\ $$$${dF}={idlBsin}\theta\:\:\:{i}={current} \\ $$$${dl}={length}\:{of}\:{wire} \\ $$$${B}={magnetic}\:{field}\:{strength} \\ $$$$\theta={angle}\:{between}\:{B}\:{and}\:{i} \\ $$
Commented by aurpeyz last updated on 26/Nov/20
thanks
$${thanks} \\ $$

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