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Question-123868




Question Number 123868 by benjo_mathlover last updated on 28/Nov/20
Answered by liberty last updated on 29/Nov/20
we begin from A^3 =A.A^2  and A^2 =8A−13I  gives A^3 =A(8A−13I)=8A^2 −13A                     = 8(8A−13I)−13A                     = 64A −104I−13A = 51A−104I            xA+yI = 51A−104I    we conclude that  { ((x=51)),((y=−104)) :}
webeginfromA3=A.A2andA2=8A13IgivesA3=A(8A13I)=8A213A=8(8A13I)13A=64A104I13A=51A104IxA+yI=51A104Iweconcludethat{x=51y=104

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