Question Number 124329 by ajfour last updated on 02/Dec/20
Commented by ajfour last updated on 02/Dec/20
$${Find}\:{maximum}\:{of}\:{shaded}\:{area}. \\ $$
Commented by mr W last updated on 02/Dec/20
$${should}\:{it}\:{not}\:{be}\:\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}×\mathrm{1}=\mathrm{1}? \\ $$
Answered by ajfour last updated on 02/Dec/20
$${A}=\mathrm{sin}\:\theta\mathrm{cos}\:\theta+\mathrm{sin}\:\phi\mathrm{cos}\:\phi \\ $$$$\:\:\:\:=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{sin}\:\mathrm{2}\theta+\mathrm{sin}\:\mathrm{2}\phi\right) \\ $$$${Yes}\:{Sir},\:{quite}\:{apparent},\:{thanks}! \\ $$