Question Number 124367 by ajfour last updated on 02/Dec/20
Commented by ajfour last updated on 02/Dec/20
$${Find}\:{maximum}\:{area}\:{of}\:\bigtriangleup{ABC}. \\ $$
Commented by mr W last updated on 02/Dec/20
$$\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{3}×\left(\frac{\mathrm{3}}{\mathrm{2}}+\mathrm{1}\right)=\frac{\mathrm{15}}{\mathrm{4}} \\ $$
Commented by mr W last updated on 04/Dec/20
Commented by ajfour last updated on 04/Dec/20
$${yes},\:{thank}\:{you}\:{Sir}. \\ $$