Question Number 124393 by n0y0n last updated on 03/Dec/20
Answered by Kunal12588 last updated on 03/Dec/20
$$\mathrm{1}.\:{l}_{\mathrm{1}} :−{i}+\mathrm{3}{j}+\mathrm{2}{k}+\nu\left(−\mathrm{3}{i}−{j}−\mathrm{4}{k}\right) \\ $$$$\left(\mathrm{5},\lambda,\mu\right)\:{lies}\:{on}\:{l}_{\mathrm{1}} \\ $$$$\Rightarrow\nu=\frac{\mathrm{5}+\mathrm{1}}{−\mathrm{3}}=−\mathrm{2} \\ $$$$\lambda=\mathrm{3}−\nu=\mathrm{5} \\ $$$$\mu=\mathrm{2}−\mathrm{4}\nu=\mathrm{10} \\ $$