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Question-124722




Question Number 124722 by I want to learn more last updated on 05/Dec/20
Answered by mr W last updated on 05/Dec/20
Commented by mr W last updated on 05/Dec/20
tan θ=((13550)/r)  (2π−2θ)r=13550  2(π−θ)r=r tan θ  2(π−θ)=tan θ  ⇒θ=1.305  ⇒r=((13550)/(tan θ))≈3689
$$\mathrm{tan}\:\theta=\frac{\mathrm{13550}}{{r}} \\ $$$$\left(\mathrm{2}\pi−\mathrm{2}\theta\right){r}=\mathrm{13550} \\ $$$$\mathrm{2}\left(\pi−\theta\right){r}={r}\:\mathrm{tan}\:\theta \\ $$$$\mathrm{2}\left(\pi−\theta\right)=\mathrm{tan}\:\theta \\ $$$$\Rightarrow\theta=\mathrm{1}.\mathrm{305} \\ $$$$\Rightarrow{r}=\frac{\mathrm{13550}}{\mathrm{tan}\:\theta}\approx\mathrm{3689} \\ $$
Commented by I want to learn more last updated on 12/Dec/20
I appreciate sir
$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{sir} \\ $$

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