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Question-125070




Question Number 125070 by Algoritm last updated on 08/Dec/20
Commented by mr W last updated on 08/Dec/20
x⊥y⊥z is not possible.  do you mean x⊥a, y⊥b, z⊥c?  but any way, you can not determine  the area of triangle with given  conditions.
$${x}\bot{y}\bot{z}\:{is}\:{not}\:{possible}. \\ $$$${do}\:{you}\:{mean}\:{x}\bot{a},\:{y}\bot{b},\:{z}\bot{c}? \\ $$$${but}\:{any}\:{way},\:{you}\:{can}\:{not}\:{determine} \\ $$$${the}\:{area}\:{of}\:{triangle}\:{with}\:{given} \\ $$$${conditions}. \\ $$
Commented by Algoritm last updated on 08/Dec/20
yes sir
$$\mathrm{yes}\:\mathrm{sir} \\ $$
Commented by Algoritm last updated on 08/Dec/20
P=a+b+c=20,  x+y+z=6, x⊥y⊥z,  area △=?
$$\mathrm{P}=\mathrm{a}+\mathrm{b}+\mathrm{c}=\mathrm{20},\:\:\mathrm{x}+\mathrm{y}+\mathrm{z}=\mathrm{6},\:\mathrm{x}\bot\mathrm{y}\bot\mathrm{z},\:\:\mathrm{area}\:\bigtriangleup=? \\ $$

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