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Question-125322




Question Number 125322 by john_santu last updated on 10/Dec/20
Commented by john_santu last updated on 10/Dec/20
question (c)
question(c)
Commented by john_santu last updated on 10/Dec/20
Commented by john_santu last updated on 10/Dec/20
is it correct ?
isitcorrect?
Commented by mr W last updated on 10/Dec/20
(c)  V=π(Rh^2 −(h^3 /3))  (dV/dt)=(dV/dh)×(dh/dt)=πh(2R−h)(dh/dt)   ...(i)  A=π(2Rh−h^2 )  (dA/dt)=(dA/dh)×(dh/dt)=2π(R−h)(dh/dt)   ...(ii)  ((dA/dt)/(dV/dt))=((2(R−h))/(h(2R−h)))  ⇒(dA/dt)=((2(R−h))/(h(2R−h)))×(dV/dt)  =((2(6−2))/(2(2×6−2)))×4=1.6 in^2 /s
(c)V=π(Rh2h33)dVdt=dVdh×dhdt=πh(2Rh)dhdt(i)A=π(2Rhh2)dAdt=dAdh×dhdt=2π(Rh)dhdt(ii)dAdtdVdt=2(Rh)h(2Rh)dAdt=2(Rh)h(2Rh)×dVdt=2(62)2(2×62)×4=1.6in2/s
Commented by john_santu last updated on 10/Dec/20
ok correct . thanks
okcorrect.thanks

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