Question Number 126070 by benjo_mathlover last updated on 17/Dec/20
Commented by liberty last updated on 17/Dec/20
$${h}\left({x}\right)=\int_{\mathrm{1}} ^{\:{x}} {f}\left({t}\right)\:{dt}\:\Leftrightarrow\:{h}'\left({x}\right)=\:{f}\left({x}\right) \\ $$$${h}'\left(\mathrm{4}\right)={f}\left(\mathrm{4}\right)=\:\mathrm{2} \\ $$$$ \\ $$