Question Number 126304 by mohammad17 last updated on 19/Dec/20
Answered by liberty last updated on 19/Dec/20
$$\left(\mathrm{1}\right)\mathrm{2}!×\mathrm{4}! \\ $$$$\left(\mathrm{3}\right)\mathrm{5}!−\mathrm{2}!×\mathrm{4}!=\mathrm{4}!×\mathrm{3} \\ $$
Answered by mr W last updated on 19/Dec/20
$$\left(\mathrm{1}\right) \\ $$$$\mathrm{2}×\mathrm{4}!=\mathrm{48} \\ $$$$\left(\mathrm{2}\right) \\ $$$$−{X}−{X}−{X}− \\ $$$$\mathrm{3}!×{P}_{\mathrm{2}} ^{\mathrm{4}} =\mathrm{72} \\ $$