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Question-126304




Question Number 126304 by mohammad17 last updated on 19/Dec/20
Answered by liberty last updated on 19/Dec/20
(1)2!×4!  (3)5!−2!×4!=4!×3
$$\left(\mathrm{1}\right)\mathrm{2}!×\mathrm{4}! \\ $$$$\left(\mathrm{3}\right)\mathrm{5}!−\mathrm{2}!×\mathrm{4}!=\mathrm{4}!×\mathrm{3} \\ $$
Answered by mr W last updated on 19/Dec/20
(1)  2×4!=48  (2)  −X−X−X−  3!×P_2 ^4 =72
$$\left(\mathrm{1}\right) \\ $$$$\mathrm{2}×\mathrm{4}!=\mathrm{48} \\ $$$$\left(\mathrm{2}\right) \\ $$$$−{X}−{X}−{X}− \\ $$$$\mathrm{3}!×{P}_{\mathrm{2}} ^{\mathrm{4}} =\mathrm{72} \\ $$

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