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Question-126482




Question Number 126482 by ayyoubmaths last updated on 20/Dec/20
Answered by Dwaipayan Shikari last updated on 20/Dec/20
lim_(x→0) (((cosx−1)/x))=−((2sin^2 (x/2))/x)=−(x^2 /(2x))=0
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{{cosx}−\mathrm{1}}{{x}}\right)=−\frac{\mathrm{2}{sin}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{{x}}=−\frac{{x}^{\mathrm{2}} }{\mathrm{2}{x}}=\mathrm{0} \\ $$

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