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Question-126572




Question Number 126572 by sdfg last updated on 22/Dec/20
Answered by liberty last updated on 22/Dec/20
 ∣a^→ +b^→ ∣^2 = ∣a^→ ∣^2 +∣b^→ ∣^2 +2∣a^→ ∣∣b^→ ∣cos α          50    = 25 +25 + 2(5)(5)cos α         cos α = 0 → α=(π/2)
a+b2=a2+b2+2a∣∣bcosα50=25+25+2(5)(5)cosαcosα=0α=π2

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