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Question-126921




Question Number 126921 by sdfg last updated on 25/Dec/20
Commented by mr W last updated on 25/Dec/20
C^→ =A^(→) +B^(→)   C^→ ′=(1/2)A^(→) +(1/2)B^(→) =(1/2)(A^→ +B^(→) )=(C^→ /2)
$$\overset{\rightarrow} {{C}}=\overset{\rightarrow} {{A}}+\overset{\rightarrow} {{B}} \\ $$$$\overset{\rightarrow} {{C}}'=\frac{\mathrm{1}}{\mathrm{2}}\overset{\rightarrow} {{A}}+\frac{\mathrm{1}}{\mathrm{2}}\overset{\rightarrow} {{B}}=\frac{\mathrm{1}}{\mathrm{2}}\left(\overset{\rightarrow} {{A}}+\overset{\rightarrow} {{B}}\right)=\frac{\overset{\rightarrow} {{C}}}{\mathrm{2}} \\ $$

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