Question Number 126987 by sdfg last updated on 25/Dec/20
Answered by mr W last updated on 26/Dec/20
$${Q}\mathrm{4} \\ $$$$\boldsymbol{{C}}=\alpha\boldsymbol{{A}}+\beta\boldsymbol{{B}} \\ $$$$\mid\boldsymbol{{C}}\mid=\sqrt{\alpha^{\mathrm{2}} \mid\boldsymbol{{A}}\mid^{\mathrm{2}} +\beta^{\mathrm{2}} \mid\boldsymbol{{B}}\mid^{\mathrm{2}} +\mathrm{2}\alpha\beta\mid\boldsymbol{{A}}\mid\mid\boldsymbol{{B}}\mid\mathrm{cos}\:\theta} \\ $$
Commented by mr W last updated on 26/Dec/20
$${Q}\mathrm{5} \\ $$$${a}_{{x}} =\mid{A}\mid\:\mathrm{cos}\:\theta \\ $$$${a}_{{y}} =\mid{A}\mid\:\mathrm{sin}\:\theta \\ $$
Commented by sdfg last updated on 31/Dec/20
$${please}\:{more}\:{detail} \\ $$$$ \\ $$