Question-127508

Question Number 127508 by mohammad17 last updated on 30/Dec/20

Commented by mohammad17 last updated on 30/Dec/20

s u c h t h a t β b e t a f u n c t i o n

Answered by Ar Brandon last updated on 30/Dec/20

β (a, b) β (a + b, c)

= \frac{Γ (a) Γ (b)}{Γ (a + b)} \cdot \frac{Γ (a + b) Γ (c)}{Γ (a + b + c)}

= \frac{Γ (a) Γ (b) Γ (c)}{Γ (a + b + c)}

= \frac{Γ (a) Γ (b + c)}{Γ (a + b + c)} \cdot \frac{Γ (b) Γ (c)}{Γ (b + c)}

= β (a, b + c) β (b, c)

Commented by mohammad17 last updated on 30/Dec/20

t h a n k y o u s i r c a n y o u h e l p m e i n a l l q u e s t i o n

Answered by Ar Brandon last updated on 30/Dec/20

β (a, b) β (a + b, c)

= \frac{Γ (a) Γ (b)}{Γ (a + b)} \cdot \frac{Γ (a + b) Γ (c)}{Γ (a + b + c)}

= \frac{Γ (a) Γ (b) Γ (c)}{Γ (a + b + c)}

= \frac{Γ (b) Γ (a + c)}{Γ (a + b + c)} \cdot \frac{Γ (a) Γ (c)}{Γ (a + c)}

= β (a, c) β (b, c + a)