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Question-127566




Question Number 127566 by Ar Brandon last updated on 30/Dec/20
Answered by bramlexs22 last updated on 30/Dec/20
(a^→ +b^→ )×(a^→ −b^→ )=a^→ ×a^→ −a^→ ×b^→ +b^→ ×a^→ −b^→ ×b^→   [ a^→ ×a^→  = 0 ; a^→ ×b^→ =−b^→ ×a^→  ]             = 0 + 2(b^→ ×a^→ )−0 = 2(b^→ ×a^→ )
(a+b)×(ab)=a×aa×b+b×ab×b[a×a=0;a×b=b×a]=0+2(b×a)0=2(b×a)
Commented by Ar Brandon last updated on 31/Dec/20
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