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Question-127740




Question Number 127740 by Algoritm last updated on 01/Jan/21
Commented by Algoritm last updated on 01/Jan/21
yellow shaded area=?
$$\mathrm{yellow}\:\mathrm{shaded}\:\mathrm{area}=? \\ $$
Commented by mr W last updated on 02/Jan/21
do you have the correct answer?  i got shaded area=((area of square)/(24)).
$${do}\:{you}\:{have}\:{the}\:{correct}\:{answer}? \\ $$$${i}\:{got}\:{shaded}\:{area}=\frac{{area}\:{of}\:{square}}{\mathrm{24}}. \\ $$
Commented by mr W last updated on 02/Jan/21
why don′t you answer this simple  question from me?
$${why}\:{don}'{t}\:{you}\:{answer}\:{this}\:{simple} \\ $$$${question}\:{from}\:{me}? \\ $$
Commented by Algoritm last updated on 02/Jan/21
yes sir
$$\mathrm{yes}\:\mathrm{sir} \\ $$
Commented by mr W last updated on 02/Jan/21
thank you sir!
$${thank}\:{you}\:{sir}! \\ $$
Answered by mr W last updated on 01/Jan/21
Commented by mr W last updated on 01/Jan/21
tan α=(1/2)  tan 2α=((2×(1/2))/(1−((1/2))^2 ))=(4/3)  β=π−2×2α=π−4α  sin β=sin 4α=((2×(4/3))/(1+((4/3))^2 ))=((24)/(25))  shaded area=((a/4)×sin 2α)^2 ×(1/(sin β))  =(a^2 /(16))×((4/5))^2 ×((25)/(24))=(a^2 /(24))
$$\mathrm{tan}\:\alpha=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{tan}\:\mathrm{2}\alpha=\frac{\mathrm{2}×\frac{\mathrm{1}}{\mathrm{2}}}{\mathrm{1}−\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\mathrm{4}}{\mathrm{3}} \\ $$$$\beta=\pi−\mathrm{2}×\mathrm{2}\alpha=\pi−\mathrm{4}\alpha \\ $$$$\mathrm{sin}\:\beta=\mathrm{sin}\:\mathrm{4}\alpha=\frac{\mathrm{2}×\frac{\mathrm{4}}{\mathrm{3}}}{\mathrm{1}+\left(\frac{\mathrm{4}}{\mathrm{3}}\right)^{\mathrm{2}} }=\frac{\mathrm{24}}{\mathrm{25}} \\ $$$${shaded}\:{area}=\left(\frac{{a}}{\mathrm{4}}×\mathrm{sin}\:\mathrm{2}\alpha\right)^{\mathrm{2}} ×\frac{\mathrm{1}}{\mathrm{sin}\:\beta} \\ $$$$=\frac{{a}^{\mathrm{2}} }{\mathrm{16}}×\left(\frac{\mathrm{4}}{\mathrm{5}}\right)^{\mathrm{2}} ×\frac{\mathrm{25}}{\mathrm{24}}=\frac{{a}^{\mathrm{2}} }{\mathrm{24}} \\ $$

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