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Question-127859




Question Number 127859 by AgnibhoMukhopadhyay last updated on 02/Jan/21
Answered by liberty last updated on 03/Jan/21
 ((3−5i)/(8+2i)) × ((8−2i)/(8−2i)) = ((24−46i−10)/(64+4))=((14−46i)/(68))   = (7/(34))−((23i)/(34))
$$\:\frac{\mathrm{3}−\mathrm{5i}}{\mathrm{8}+\mathrm{2i}}\:×\:\frac{\mathrm{8}−\mathrm{2i}}{\mathrm{8}−\mathrm{2i}}\:=\:\frac{\mathrm{24}−\mathrm{46i}−\mathrm{10}}{\mathrm{64}+\mathrm{4}}=\frac{\mathrm{14}−\mathrm{46i}}{\mathrm{68}} \\ $$$$\:=\:\frac{\mathrm{7}}{\mathrm{34}}−\frac{\mathrm{23i}}{\mathrm{34}} \\ $$

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