Question-128458 Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 128458 by SLVR last updated on 07/Jan/21 Commented by BHOOPENDRA last updated on 07/Jan/21 Givenf(f(1))=0,f(f(2))=0i.eequationf(x)=0hastworootf(1)andf(2)f(1)+f(2)=−αandf(1).f(2)=βso5+3α+2β=−αand(1+α+β)(4+2α+β)⇒2α+β=−52⇒(1−54−β2)(4−52)=β⇒β=−32∴f(0)=β=−32 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-62923Next Next post: Three-friends-Boakye-kwame-and-kojo-thinking-that-they-are-decieving-their-parents-decided-to-take-turns-to-run-away-from-their-parent-Boakye-run-away-on-monday-of-the-first-week-After-how-m Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.