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Question-128561




Question Number 128561 by 777316 last updated on 08/Jan/21
Answered by Dwaipayan Shikari last updated on 08/Jan/21
lim_(x→0) cosx+(((1−cosx)/(sinx)))=1+((2sin^2 (x/2))/(sinx))=1
$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}{cosx}+\left(\frac{\mathrm{1}−{cosx}}{{sinx}}\right)=\mathrm{1}+\frac{\mathrm{2}{sin}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{{sinx}}=\mathrm{1} \\ $$

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