Question Number 129132 by BHOOPENDRA last updated on 13/Jan/21
Answered by Dwaipayan Shikari last updated on 13/Jan/21
$$\mathscr{L}^{−\mathrm{1}} \left(\frac{\mathrm{6}{as}}{\left(\mathrm{9}{s}^{\mathrm{2}} +{a}^{\mathrm{2}} \right)}\right)=\frac{\mathrm{1}}{\mathrm{9}}\mathscr{L}^{−\mathrm{1}} \left(\frac{\mathrm{2}\left(\frac{{a}}{\mathrm{3}}\right){s}}{\left({s}^{\mathrm{2}} +\left(\frac{{a}}{\mathrm{3}}\right)^{\mathrm{2}} \right)}\right)=\frac{{t}}{\mathrm{9}}{sin}\left(\frac{{at}}{\mathrm{3}}\right) \\ $$
Commented by BHOOPENDRA last updated on 13/Jan/21
$${thanks}\:{sir} \\ $$