Menu Close

Question-129132




Question Number 129132 by BHOOPENDRA last updated on 13/Jan/21
Answered by Dwaipayan Shikari last updated on 13/Jan/21
L^(−1) (((6as)/((9s^2 +a^2 ))))=(1/9)L^(−1) (((2((a/3))s)/((s^2 +((a/3))^2 ))))=(t/9)sin(((at)/3))
$$\mathscr{L}^{−\mathrm{1}} \left(\frac{\mathrm{6}{as}}{\left(\mathrm{9}{s}^{\mathrm{2}} +{a}^{\mathrm{2}} \right)}\right)=\frac{\mathrm{1}}{\mathrm{9}}\mathscr{L}^{−\mathrm{1}} \left(\frac{\mathrm{2}\left(\frac{{a}}{\mathrm{3}}\right){s}}{\left({s}^{\mathrm{2}} +\left(\frac{{a}}{\mathrm{3}}\right)^{\mathrm{2}} \right)}\right)=\frac{{t}}{\mathrm{9}}{sin}\left(\frac{{at}}{\mathrm{3}}\right) \\ $$
Commented by BHOOPENDRA last updated on 13/Jan/21
thanks sir
$${thanks}\:{sir} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *