Question Number 129856 by mohammad17 last updated on 20/Jan/21
Commented by mohammad17 last updated on 20/Jan/21
$${how}\:{can}\:{solve}\:{this} \\ $$
Answered by MJS_new last updated on 20/Jan/21
$${rr}:\:\frac{\mathrm{4}}{\mathrm{10}}×\frac{\mathrm{3}}{\mathrm{9}}=\frac{\mathrm{2}}{\mathrm{15}} \\ $$$$\left.\begin{matrix}{{rb}:\:\frac{\mathrm{4}}{\mathrm{10}}×\frac{\mathrm{6}}{\mathrm{9}}=\frac{\mathrm{4}}{\mathrm{15}}}\\{{br}:\:\frac{\mathrm{6}}{\mathrm{10}}×\frac{\mathrm{4}}{\mathrm{9}}=\frac{\mathrm{4}}{\mathrm{15}}}\end{matrix}\right\}\:\frac{\mathrm{8}}{\mathrm{15}} \\ $$$${bb}:\:\frac{\mathrm{6}}{\mathrm{10}}×\frac{\mathrm{5}}{\mathrm{9}}=\frac{\mathrm{1}}{\mathrm{3}} \\ $$