Question Number 130713 by harckinwunmy last updated on 28/Jan/21
Commented by EDWIN88 last updated on 28/Jan/21
$${ans}:\:{B} \\ $$
Answered by EDWIN88 last updated on 28/Jan/21
$${g}\left({x}\right)={a}\left({x}+\mathrm{2}\right)\left({x}−\mathrm{3}\right)\left({x}−\mathrm{6}\right) \\ $$$${g}\left(\mathrm{0}\right)={a}\left(\mathrm{2}\right)\left(−\mathrm{3}\right)\left(−\mathrm{6}\right)<\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{36}{a}<\mathrm{0};\:{a}<\mathrm{0} \\ $$$$\left(\mathrm{1}\right){g}\left(−\mathrm{3}\right)={a}\left(−\mathrm{1}\right)\left(−\mathrm{6}\right)\left(−\mathrm{9}\right)>\mathrm{0} \\ $$$$\left(\mathrm{2}\right){g}\left(−\mathrm{1}\right)={a}\left(\mathrm{1}\right)\left(−\mathrm{4}\right)\left(−\mathrm{7}\right)<\mathrm{0} \\ $$$$\left(\mathrm{3}\right){g}\left(\mathrm{4}\right)={a}\left(\mathrm{6}\right)\left(\mathrm{1}\right)\left(−\mathrm{2}\right)>\mathrm{0} \\ $$$$\left(\mathrm{4}\right){g}\left(\mathrm{5}\right)={a}\left(\mathrm{7}\right)\left(\mathrm{2}\right)\left(−\mathrm{1}\right)>\mathrm{0} \\ $$