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Question-13830




Question Number 13830 by tawa tawa last updated on 24/May/17
Answered by ajfour last updated on 24/May/17
V=πR^2 H+(2/3)πR^2 h        =πR^2 (H+((2R)/3))         (∵ as h=R)     ≈((22)/7)×25(10+((10)/3))     ≈((22×250×4)/(21))     ≈1000(1+(1/(21)))≈1000+((1000−50)/(20))   V≈1000+50−2.5=1047.5 ft^3
$${V}=\pi{R}^{\mathrm{2}} {H}+\frac{\mathrm{2}}{\mathrm{3}}\pi{R}^{\mathrm{2}} {h}\:\:\: \\ $$$$\:\:\:=\pi{R}^{\mathrm{2}} \left({H}+\frac{\mathrm{2}{R}}{\mathrm{3}}\right)\:\:\:\:\:\:\:\:\:\left(\because\:{as}\:{h}={R}\right) \\ $$$$\:\:\:\approx\frac{\mathrm{22}}{\mathrm{7}}×\mathrm{25}\left(\mathrm{10}+\frac{\mathrm{10}}{\mathrm{3}}\right) \\ $$$$\:\:\:\approx\frac{\mathrm{22}×\mathrm{250}×\mathrm{4}}{\mathrm{21}} \\ $$$$\:\:\:\approx\mathrm{1000}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{21}}\right)\approx\mathrm{1000}+\frac{\mathrm{1000}−\mathrm{50}}{\mathrm{20}} \\ $$$$\:{V}\approx\mathrm{1000}+\mathrm{50}−\mathrm{2}.\mathrm{5}=\mathrm{1047}.\mathrm{5}\:{ft}^{\mathrm{3}} \: \\ $$
Commented by ajfour last updated on 24/May/17
thanks for your questions.
$${thanks}\:{for}\:{your}\:{questions}. \\ $$
Commented by tawa tawa last updated on 24/May/17
God bless you sir. i really appreciate your effort.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort}. \\ $$

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