Question-14073

Question Number 14073 by tawa tawa last updated on 27/May/17

Commented by ajfour last updated on 27/May/17

Commented by ajfour last updated on 27/May/17

Commented by ajfour last updated on 27/May/17

Q (1) .

A = \frac{1}{2} (2 x) y

y = r \sec θ + r

= r (1 + \sec θ)

x = y \cot θ

= r (1 + \sec θ) \cot θ

A = x y = r^{2} (1 + \sec^{2} θ) \cot θ .

Commented by tawa tawa last updated on 27/May/17

God bless you sir .

Answered by ajfour last updated on 27/May/17

Q (2) .

h = r cosec θ + r

h = r (1 + cosec θ)

R = h \tan θ = r (1 + cosec θ) \tan θ

V = \frac{1}{3} π R^{2} h

V = \frac{1}{3} r^{3} {(1 + cosec θ)}^{3} \tan^{2} θ .

Commented by tawa tawa last updated on 27/May/17

God bless you sir .