Question Number 14079 by Tinkutara last updated on 27/May/17
Commented by ajfour last updated on 27/May/17
$${tbreshold}\:{frequency}\:= \\ $$$$\:\:\:\:\:\:\:\left({speed}\:{of}\:{e}.{m}.\:{wave}\right)/\left({threshold}\:{wavelength}\right) \\ $$$$\boldsymbol{\nu}_{\mathrm{0}} =\frac{\boldsymbol{{c}}}{\boldsymbol{\lambda}_{\mathrm{0}} }\:=\frac{\left(\mathrm{3}×\mathrm{10}^{\mathrm{8}} {m}/{s}\right)}{\left(\mathrm{6800}×\mathrm{10}^{−\mathrm{10}} {m}\right)} \\ $$$$\:\:\:\:\:=\:\frac{\mathrm{300}}{\mathrm{68}}×\mathrm{10}^{\mathrm{14}} {Hz} \\ $$$$\:\:\:\:\:=\:\frac{\mathrm{75}}{\mathrm{17}}×\mathrm{10}^{\mathrm{14}} {Hz}\:\:\approx\:\mathrm{4}.\mathrm{41}×\mathrm{10}^{\mathrm{14}} {Hz}\:. \\ $$
Commented by Tinkutara last updated on 27/May/17
$$\mathrm{Thanks}. \\ $$