Menu Close

Question-144300

Tinku Tara 0 Comments
Pin




Question Number 144300 by mathdanisur last updated on 24/Jun/21
Answered by Rasheed.Sindhi last updated on 25/Jun/21
(x+1)^(2n+1) −a^(2n+1) =x(x+1)Q(x)+ux+v For x∈Z For x=0 1−a^(2n+1) =v For x=−1 −a^(2n+1) =−u+v −a^(2n+1) =−u+1−a^(2n+1) −u+1=0⇒u=1 R(x)=ux+v=(1)x+1−a^(2n+1) =x+1−a^(2n+1)
(x+1)2n+1−a2n+1=x(x+1)Q(x)+ux+vForx∈ZForx=01−a2n+1=vForx=−1−a2n+1=−u+v−a2n+1=−u+1−a2n+1−u+1=0⇒u=1R(x)=ux+v=(1)x+1−a2n+1=x+1−a2n+1
Commented by mathdanisur last updated on 25/Jun/21
thanks Sir cool
thanksSircool

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *