Question-144564

Question Number 144564 by imjagoll last updated on 26/Jun/21

Commented by justtry last updated on 26/Jun/21

0 ? ?

Answered by liberty last updated on 26/Jun/21

\lim_{x \to - \infty} (\frac{{(x - \sqrt{x^{2} - 2 x + 1})}^{2021}}{x^{2021}}) + \lim_{x \to - \infty} (\frac{{(x - \sqrt{x^{2} + 5})}^{2021}}{x^{2021}})

= \lim_{x \to - \infty} {(\frac{x + x \sqrt{1 - {2 x}^{- 1} + x^{- 2}}}{x})}^{2021} + \lim_{x \to - \infty} {(\frac{x + x \sqrt{1 + {5 x}^{- 2}}}{x})}^{2021}

= 2^{2021} + 2^{2021} = 2^{2022}

Commented by justtry last updated on 26/Jun/21

n i c e, t h a n k y o u

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