Question Number 145012 by mim24 last updated on 01/Jul/21
Answered by ArielVyny last updated on 01/Jul/21
$${lim}\left({x}^{−\frac{\mathrm{1}}{{x}}} \right)\:\:\left({x}\rightarrow\mathrm{0}\right) \\ $$$${lim}\left({e}^{−\frac{\mathrm{1}}{{x}}{lnx}} \right)\left({x}\rightarrow\mathrm{0}^{+} \right)=+\infty \\ $$$$ \\ $$