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Question-145436




Question Number 145436 by mathdanisur last updated on 04/Jul/21
Commented by justtry last updated on 05/Jul/21
Commented by mathdanisur last updated on 05/Jul/21
thanks Ser, but wrong  (1+a)^k <=1+ka  if  k∈[0;1]
$${thanks}\:{Ser},\:{but}\:{wrong} \\ $$$$\left(\mathrm{1}+{a}\right)^{{k}} <=\mathrm{1}+{ka}\:\:{if}\:\:{k}\in\left[\mathrm{0};\mathrm{1}\right] \\ $$

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