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Question-145701

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Question Number 145701 by alcohol last updated on 07/Jul/21
Commented by MJS_new last updated on 07/Jul/21
1. square−2×(square−quarter circle)= =−square+2×quarter circle= =half circle−square=4^2 π/2−4^2 = =8π−16 2. trapezoid−rectangular−half circle= =((6+8)/2)×4−4×2−2^2 π/2=20−2π
1.square−2×(square−quartercircle)==−square+2×quartercircle==halfcircle−square=42π/2−42==8π−162.trapezoid−rectangular−halfcircle==6+82×4−4×2−22π/2=20−2π
Answered by iloveisrael last updated on 07/Jul/21
(1) shaded area = 2((1/4)π(4)^2 −(1/2)(4)^2 ) = 2(4π−8)=8π−16
(1)shadedarea=2(14π(4)2−12(4)2)=2(4π−8)=8π−16
Answered by iloveisrael last updated on 07/Jul/21
(2) shaded area=(((4+6)/2)).4−(1/2)π(2)^2 = 20−2π
(2)shadedarea=(4+62).4−12π(2)2=20−2π
Commented by alcohol last updated on 07/Jul/21
please explain this thanks
pleaseexplainthisthanks

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