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Question-146606




Question Number 146606 by iloveisrael last updated on 14/Jul/21
Answered by som(math1967) last updated on 14/Jul/21
x+(√(x^2 −1))+(1/(x−(√(x^2 −1))))=20  ((x^2 −x^2 +1+1)/(x−(√(x^2 −1))))=20  (1/(x−(√(x^2 −1))))=10  x−(√(x^2 −1))=(1/(10))  again (1/(x−(√(x^2 −1))))=10  ((x+(√(x^2 −1)))/(x^2 −x^2 +1))=10  x+(√(x^2 −1))=10  ∴2x=10+(1/(10))=((101)/(10))  x=((101)/(20))  now x^2 +(√(x^4 −1))+(1/(x^2 +(√(x^4 −1))))  x^2 +(√(x^4 −1)) +((x^2 −(√(x^4 −1)))/(x^4 −x^4 +1))  =2x^2 =2×(((101)/(20)))^2
x+x21+1xx21=20x2x2+1+1xx21=201xx21=10xx21=110again1xx21=10x+x21x2x2+1=10x+x21=102x=10+110=10110x=10120nowx2+x41+1x2+x41x2+x41+x2x41x4x4+1=2x2=2×(10120)2

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