Question-146606 Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 146606 by iloveisrael last updated on 14/Jul/21 Answered by som(math1967) last updated on 14/Jul/21 x+x2−1+1x−x2−1=20x2−x2+1+1x−x2−1=201x−x2−1=10x−x2−1=110again1x−x2−1=10x+x2−1x2−x2+1=10x+x2−1=10∴2x=10+110=10110x=10120nowx2+x4−1+1x2+x4−1x2+x4−1+x2−x4−1x4−x4+1=2x2=2×(10120)2 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: cos-x-1-sin-x-2cos-x-cos-x-sin-x-in-5pi-7pi-2-Next Next post: Question-15534 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.