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Question-14661




Question Number 14661 by ajfour last updated on 03/Jun/17
Commented by ajfour last updated on 03/Jun/17
Prove Pythagoras theorem  with the aid of image above .
$$\boldsymbol{{Prove}}\:\boldsymbol{{Pythagoras}}\:\boldsymbol{{theorem}} \\ $$$${with}\:{the}\:{aid}\:{of}\:{image}\:{above}\:. \\ $$
Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 03/Jun/17
h^2 =4×(1/2)bp+(b−p)^2 =b^2 +p^2  .■
$${h}^{\mathrm{2}} =\mathrm{4}×\frac{\mathrm{1}}{\mathrm{2}}{bp}+\left({b}−{p}\right)^{\mathrm{2}} ={b}^{\mathrm{2}} +{p}^{\mathrm{2}} \:.\blacksquare \\ $$
Commented by ajfour last updated on 03/Jun/17
how nice, you were quick !
$${how}\:{nice},\:{you}\:{wer}\boldsymbol{{e}}\:\boldsymbol{{q}}{uick}\:! \\ $$

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