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Question-146776




Question Number 146776 by mathdanisur last updated on 15/Jul/21
Commented by mr W last updated on 15/Jul/21
AB^2 =20^2 −x^2 =(20+5)^2 +10^2 −2×25×10 cos C  AD^2 =x^2 =5^2 +10^2 −2×5×10 cos C  ⇒20^2 −x^2 =(20+5)^2 +10^2 +5(x^2 −5^2 −10^2 )  ⇒x^2 =50  ⇒x=5(√2)
AB2=202x2=(20+5)2+1022×25×10cosCAD2=x2=52+1022×5×10cosC202x2=(20+5)2+102+5(x252102)x2=50x=52
Commented by mathdanisur last updated on 15/Jul/21
thank you Ser
thankyouSer

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