Question-146776 Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 146776 by mathdanisur last updated on 15/Jul/21 Commented by mr W last updated on 15/Jul/21 AB2=202−x2=(20+5)2+102−2×25×10cosCAD2=x2=52+102−2×5×10cosC⇒202−x2=(20+5)2+102+5(x2−52−102)⇒x2=50⇒x=52 Commented by mathdanisur last updated on 15/Jul/21 thankyouSer Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: d-2-y-dx-2-dy-dx-6y-2-sin-x-Find-y-Next Next post: Find-the-modulus-of-a-complex-number-Z-cos-40-i-sin-40-1- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.