Question-146817 Tinku Tara June 4, 2023 Algebra 0 Comments FacebookTweetPin Question Number 146817 by mathdanisur last updated on 15/Jul/21 Answered by mindispower last updated on 15/Jul/21 ⇔y(x+y)+z(x+z)(x+y)(x+z)⩾y+z….y(x+y)+z(x+z)=x(y+z)+y2+z2⩾x(y+z)+12(y+z)2=(y+z)(x+12(y+z))=(y+z)(12((x+y)+(x+z)))⩾(y+z).12.2(x+y)(x+z)=(y+z)(x+y)(x+z)⇒y(x+y)+z(x+z)(x+y)(x+z)⩾(y+z)(x+y)(x+z)(x+y)(x+z)=y+z Commented by mathdanisur last updated on 16/Jul/21 thankyouSer Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: 2x-1-3x-dx-Next Next post: discussthesymmetryofthefollowingcurves-squareofx-squareofy-1- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.