Question Number 147232 by Tawa11 last updated on 19/Jul/21
Commented by Rasheed.Sindhi last updated on 19/Jul/21
$${Square}−{quarter}\:{circle}\:{of}\:{radius}\:\mathrm{9} \\ $$$$\mathrm{9}^{\mathrm{2}} −\frac{\pi.\mathrm{9}^{\mathrm{2}} }{\mathrm{4}}=\frac{\mathrm{324}−\mathrm{81}\pi}{\mathrm{4}} \\ $$
Commented by Tawa11 last updated on 19/Jul/21
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$