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Question-147232




Question Number 147232 by Tawa11 last updated on 19/Jul/21
Commented by Rasheed.Sindhi last updated on 19/Jul/21
Square−quarter circle of radius 9  9^2 −((π.9^2 )/4)=((324−81π)/4)
$${Square}−{quarter}\:{circle}\:{of}\:{radius}\:\mathrm{9} \\ $$$$\mathrm{9}^{\mathrm{2}} −\frac{\pi.\mathrm{9}^{\mathrm{2}} }{\mathrm{4}}=\frac{\mathrm{324}−\mathrm{81}\pi}{\mathrm{4}} \\ $$
Commented by Tawa11 last updated on 19/Jul/21
Thanks sir. I appreciate.
$$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$

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