Question Number 148113 by mathdanisur last updated on 25/Jul/21
Answered by liberty last updated on 25/Jul/21
$$\:{Hatched}\:{area}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{8}\right)^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\right)−\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\mathrm{4}\right)^{\mathrm{2}} \\ $$$$=\mathrm{16}\sqrt{\mathrm{3}}−\mathrm{8}\pi \\ $$
Commented by mathdanisur last updated on 25/Jul/21
$${Thanks}\:{Ser},\:{con}\:{you}\:{please}\:{write} \\ $$$${a}\:{longer}\:{version} \\ $$