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Question-148113




Question Number 148113 by mathdanisur last updated on 25/Jul/21
Answered by liberty last updated on 25/Jul/21
 Hatched area = (1/2)(8)^2 ((1/2)(√3))−(1/2)π(4)^2   =16(√3)−8π
$$\:{Hatched}\:{area}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{8}\right)^{\mathrm{2}} \left(\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{3}}\right)−\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\mathrm{4}\right)^{\mathrm{2}} \\ $$$$=\mathrm{16}\sqrt{\mathrm{3}}−\mathrm{8}\pi \\ $$
Commented by mathdanisur last updated on 25/Jul/21
Thanks Ser, con you please write  a longer version
$${Thanks}\:{Ser},\:{con}\:{you}\:{please}\:{write} \\ $$$${a}\:{longer}\:{version} \\ $$

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