Question-148155

Question Number 148155 by Khalmohmmad last updated on 25/Jul/21

Answered by Rasheed.Sindhi last updated on 26/Jul/21

x + \frac{1}{x} = - 1 \Rightarrow x^{2} + x + 1 = 0

x = ω, ω^{2}

x = ω

x^{1400} + x^{1363} + x^{37}

= ω^{1400} + ω^{1363} + ω^{37}

= ω^{1400 m o d 3} + ω^{1363 m o d 3} + ω^{37 m o d 3}

= ω^{2} + ω + ω = - 1 + ω

x = ω^{2}

= {(ω^{2})}^{2} + ω^{2} + ω^{2}

= ω . ω^{3} + ω^{2} + ω^{2}

= ω + ω^{2} + ω^{2}

= - 1 + ω^{2}