Menu Close

Question-148522

Tinku Tara 0 Comments
Pin




Question Number 148522 by mathdanisur last updated on 28/Jul/21
Answered by Rasheed.Sindhi last updated on 29/Jul/21
P(x)=16x^2 +24x+9 Q(x)=x^3 −3x^2 +2x+2 If x=−1.25 ((P^3 +Q^3 )/(P^2 −PQ+Q^2 ))+((P^3 −Q^3 )/(P^2 +PQ+Q^2 ))=? ((P^3 +Q^3 )/(P^2 −PQ+Q^2 ))+((P^3 −Q^3 )/(P^2 +PQ+Q^2 )) =(P+Q)+(P−Q) =2P=2(16x^2 +24x+9) =2(16(−(5/4))^2 +24(−(5/4))+9) =2(16(((25)/(16)))−6(5)+9) =2(25−30+9)=2(4)=8
P(x)=16x2+24x+9Q(x)=x3−3x2+2x+2Ifx=−1.25P3+Q3P2−PQ+Q2+P3−Q3P2+PQ+Q2=?P3+Q3P2−PQ+Q2+P3−Q3P2+PQ+Q2=(P+Q)+(P−Q)=2P=2(16x2+24x+9)=2(16(−54)2+24(−54)+9)=2(16(2516)−6(5)+9)=2(25−30+9)=2(4)=8
Commented by mathdanisur last updated on 28/Jul/21
Cool Ser, thank you
CoolSer,thankyou
Answered by Olaf_Thorendsen last updated on 28/Jul/21
R = ((P^3 +Q^3 )/(P^3 −PQ+Q^2 ))+((P^3 −Q^3 )/(P^3 +PQ+Q^2 )) R = (((P+Q)(P^2 −PQ+Q^2 ))/(P^3 −PQ+Q^2 ))+(((P−Q)(P^2 +PQ+Q^2 ))/(P^3 +PQ+Q^2 )) R = P+Q+P−Q = 2P R(−(5/4)) = 2(16.((25)/(16))−24.(5/4)+9) R(−(5/4)) = 8
R=P3+Q3P3−PQ+Q2+P3−Q3P3+PQ+Q2R=(P+Q)(P2−PQ+Q2)P3−PQ+Q2+(P−Q)(P2+PQ+Q2)P3+PQ+Q2R=P+Q+P−Q=2PR(−54)=2(16.2516−24.54+9)R(−54)=8
Commented by mathdanisur last updated on 28/Jul/21
Cool Ser, thank you
CoolSer,thankyou

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *